A coworker posted something today about Manhattanhenge occuring on May 30 of this year. That’s when sunset aligns with the east-west grid of Manhattan. The streets are offset from true east-west by 28.9 degrees, according to Wikipedia. So I went to Wolfram Alpha to figure out the solar azimuth on that day. It said 30 degrees 30 minutes. Wait a second, that’s not 28.9 degrees! So initially I was confused. However, you’ll note that it indicates an altitude of -1 degrees. Because of refraction, the sun appears higher than it actually is, in this case about a degree. Since the sun rises and sets at an angle to the horizon, the azimuth is also effected. Furthermore, sunset is the point at which the trailing edge vanishes. For dating Manhattanhenge, you probably want the leading edge so that it sits right on top of the street. The angular diameter of the sun is 31 arc-minutes. So you want the date when the azimuth is at 28.9 degrees and the altitude is about 30 minutes. That gives you May 30th at 8:13pm. It gives 29 degrees, close enough to 28.9. However, the azimuth is +30 minutes. Visual sunset is closer to an altitude of -1 degrees, so I’d think the correct altitude to look for would be -30 minutes. However the astronomers that gave the 30th as the date perhaps used astronomical sunset instead of visual sunset.
The Hayden Planetarium gives 8:17pm as the time of Manhattanhenge. For that date and time, Wolfram Alpha provides an altitude of -10 minutes, and an azimuth of 29 degrees 40 minutes. Perhaps the altitude of -10 minutes is a better number for when the leading edge of the sun will hit the street.
Anyhow, you can get pretty close with just Wolfram Alpha and some simple geometry. I’m really loving that site.
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update: I found a better number for the shift in the apparent position of the sun at sunset, about 35 minutes. The -1 degree altitude reported at sunset by WA is off, or perhaps it has been rounded. If you back out the diameter of the sun, which is 31 minutes, that’s pretty close to the numbers WA gives for Hayden Planetarium’s date and time. So with a bit of extra knowledge, you can accurately find the date and time of Manhattanhenge from Wolfram Alpha. It won’t solve for it, or at least I can’t figure out how to ask it for dates and times where the azimuth is 28.9 and the altitude is -5 or -10 minutes, but you can at least do a quick search around likely dates to find the right numbers.
Posted by Ken Ellis
Posted by Ken Ellis
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